Re: [1904.2 TF] Expected Forwarding Behavior?

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What are OAM A and OAM Z exactly, in IEEE terms? Are these OAM Clients?

For OAM Client A to talk to OAM Client Z, there should exist a L2 path from TX interface of OAM sublayer A to RX interface of OAM sublayer Z. You diagram does not show any such path.

-Glen

From: Kevin Noll <kevin.noll@xxxxxxxxxxxx>
Sent: Thursday, October 29, 2020 4:10 PM
To: Glen Kramer <glen.kramer@xxxxxxxxxxxx>
Cc: stds-1904-2-TF@xxxxxxxxxxxxxxxxx
Subject: Re: [1904.2 TF] Expected Forwarding Behavior?

I should have asked my question more specifically...

What happens if OAM A wants to talk to OAM Z via VLC?

Sent from my mobile device

On Oct 29, 2020, at 6:38 PM, Glen Kramer <glen.kramer@xxxxxxxxxxxx> wrote:

The OAMPDUs received by the port on the left (MAC A) will be delivered to OAM client located above OAM SL Z (not shown). This is one direction of the use case described in 8A.3.

<image002.png>

The diagram below corresponds to the direction from Station S to Manager M. Port A below is the same as Bridge Y Port 0 here, port Z is the same Port M (Manager) here. The diagram below shows only one intermediate bridge, but there can be any number of them.

-Glen

From: Kevin Noll <kevin.noll@xxxxxxxxxxxx>
Sent: Wednesday, October 28, 2020 12:48 PM
To: STDS-1904-2-TF@xxxxxxxxxxxxxxxxx
Subject: [1904.2 TF] Expected Forwarding Behavior?

Glen, et al,

Given the topology and rule in the picture below, what is the expected behavior?

<image001.png>

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